if sin theta equal to 1 by 3 find the value of 1 + cot square theta
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Step-by-step explanation:
sin theta= 1/3
p=1,h=3 sin theta=p/h
b^2=√3^2-√1^2
b^2=9-1
b^2=8
b=√8
1+cot= 1+√8/3
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