Question

Hcf and lcm of two no are 9 and 459 respectively. if one of no is 27 find the other no

Answer 1

Answer:

second number = 153

Explanation:

Let first number = a,

second number = b

a = 27 ( given )

HCF(a,b) = 9

and

LCM (a,b) = 459

To find:

Value of b

solution:

We know that,

$\boxed {product \: of \: two \: numbers\\ = product\: of their\:HCF \:and \:LCM }$

$\implies b = \frac{HCF \times LCM}{a}$

$\implies b = \frac{9\times 459}{27}$

After cancellation, we get

$\implies b = 153$

Therefore,

second number = b = 153

••••

Answer 2

Answer:

The second number is 153