Question

HCF and LCM of two numbers is12&72.if the sum of these numbers is60 then find one number of these numbers..

Answer 1

Step-by-step explanation:

HCF=12

LCM=72

Sum of numbers =60

Let a number be x

and number be 60-x.

Product of numbers = HCF × LCM

$x \times (60 - x) = 12 \times 72 \\ 60x - x {}^{2} = 864 \\ x {}^{2} - 60x + 864 = 0$

Now we solve this quadratic equation

$x {}^{2} - 36x - 24x + 864 = 0 \\ x(x - 36) - 24(x - 36) = 0 \\( x - 24)(x - 36) = 0 \\ x = 24 \: or \: 36</p><p>$

Answer 2

Answer is in picture....❤️