Question

Hcf of 12x²yz and 16xyz²is 4xyz
$\sqrt{ \frac{ {x}^{2} }{ {y}^{2} {z}^{6} } } = {xy}^{ - 1} {z}^{ - 3}$
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Answer 1

Step-by-step explanation:

Hcf of 12x²yz and 16xyz²is 4xyz

$\sqrt{ \frac{ {x}^{2} }{ {y}^{2} {z}^{6} } } = {xy}^{ - 1} {z}^{ - 3}$

Answer 2

Answer:

Hcf of 12x²yz and 16xyz²is 4xyz

$\sqrt{ \frac{ {x}^{2} }{ {y}^{2} {z}^{6} } } = {xy}^{ - 1} {z}^{ - 3}$