Math, asked by rajesjaiswal0, 1 month ago

Hcf of 12x²yz and 16xyz²is 4xyz
 \sqrt{ \frac{ {x}^{2} }{ {y}^{2} {z}^{6}   } } =   {xy}^{ - 1}  {z}^{ - 3}

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Answered by pratham7777775
2

Step-by-step explanation:

Hcf of 12x²yz and 16xyz²is 4xyz

 \sqrt{ \frac{ {x}^{2} }{ {y}^{2} {z}^{6} } } = {xy}^{ - 1} {z}^{ - 3}

Answered by brainlysrijanuknown2
14

Answer:

Hcf of 12x²yz and 16xyz²is 4xyz

 \sqrt{ \frac{ {x}^{2} }{ {y}^{2} {z}^{6} } } = {xy}^{ - 1} {z}^{ - 3}

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