HCF of 1620,1725 and 255
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Answered by
2
Answer:
H.C.F = 15
its right.....
Answered by
1
Answer:
Let’s start with 1620 and 1725.
Apply the division lemma on 1725 and 1620,
1725 = (1620 × 1) + 105
Since the remainder is not equal to zero,
Apply lemma again on 1620 and 105. We get,
1620 = (105 × 15) + 45
Since the remainder is not equal to zero, apply lemma again on 105 and 45. We get,
105 = (45 × 2) + 15
Since the remainder is not equal to zero, apply lemma again on 45 and 15. We get,
45 = (15 × 3) + 0
The remainder has now become zero.
⇒ HCF (1620, 1725) = 15
Now we have to find HCF of 255 and 15.
Similarly, apply lemma on 225 and 15.
We get,
225 = (15 × 15) + 0
Since, the remainder is equal to 0.
⇒ HCF (225, 15) = 15
Therefore, HCF (1620, 1725, 225) = 15.....
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