Math, asked by cavenkat459, 7 months ago

HCF of (2^2*3^3*5^5), (2^3 x 3^2 x 5^2 x 7) and (2^4x 3^4 x 5 x 7^2 x 11) is​

Answers

Answered by AarchiChhabria
1

Answer:

2²×3³×5⁵

2³×3²×5²×7

2⁴×3⁴×5×7²

so

HCF= 2²×3²×5= 4×9×5=180

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