Math, asked by GKSGOUTAM81251, 9 months ago

HCF of $(2^3\times3^2\times5),(2^2\times3^3\times5^2)$ and $(2^4\times3\times5^3\times7)$is $105$ $60$ $30$ $48$

Answers

Answered by amitnrw
6

Given :  2³.3².5  ,  2².3³.5²   and 2⁴.3.5⁷

To Find :  HCF

Solution:

HCF   - Highest common factor

use xᵃ.xᵇ=xᵃ⁺ᵇ

 2³.3².5  = 2².2.3.3.5   =  

 2².3³.5² = 2².3².3,5.5

 2⁴.3.5⁷  =2².2².3.5.5⁶

Common factors  are 2².3 .5

= 4.3.5

= 60

HCF   of 2³.3².5  ,  2².3³.5²   and 2⁴.3.5⁷    is 60

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