HCF of $(2^3\times3^2\times5),(2^2\times3^3\times5^2)$ and $(2^4\times3\times5^3\times7)$is $105$ $60$ $30$ $48$
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Given : 2³.3².5 , 2².3³.5² and 2⁴.3.5⁷
To Find : HCF
Solution:
HCF - Highest common factor
use xᵃ.xᵇ=xᵃ⁺ᵇ
2³.3².5 = 2².2.3.3.5 =
2².3³.5² = 2².3².3,5.5
2⁴.3.5⁷ =2².2².3.5.5⁶
Common factors are 2².3 .5
= 4.3.5
= 60
HCF of 2³.3².5 , 2².3³.5² and 2⁴.3.5⁷ is 60
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