hcf of 219,1321,2320,8526
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we first find hcf of 219,8526
8526=219*38+204
219=204*1+15
204=15*13+9
15=9*1+6
9=6*1+3
6=3*2+0
hcf of 219,8526=3
we now find hcf of 1321,2320
2320=1321*1+999
1321=999*1+322
999=322*3+33
322=33*9+25
33=25*1+8
25=8*3+1
8=1*8+0
hcf of 1321,2320=1
so,
hcf of 219,1321,2320,8526=hcf (3,1)=1
8526=219*38+204
219=204*1+15
204=15*13+9
15=9*1+6
9=6*1+3
6=3*2+0
hcf of 219,8526=3
we now find hcf of 1321,2320
2320=1321*1+999
1321=999*1+322
999=322*3+33
322=33*9+25
33=25*1+8
25=8*3+1
8=1*8+0
hcf of 1321,2320=1
so,
hcf of 219,1321,2320,8526=hcf (3,1)=1
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1
Answer:
HCF of 219,1321,2320,8526 = 1
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