Hcf of 2710 and 55 using Euclid's algorithm
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Answered by
3
Answer:
the HCF of 210 and 55
210=55*3+45
55=45*1+10
45=10*4+5
10=5*2+0
therefore 5 is the hcf
5=210x+55y
Answered by
1
Answer:
210=55×3+45
55=45×1+18
45=10×4+5
10=5×2+10
5 is the hcf
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