HCF of 2800,1680,1200 by prime factorization
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Answer:
2800 = 2×2×2×2×5×5×7
1680 = 2×2×2×2×3×5×7
1200 = 2×2×2×2×3×5×5
hcf = 2×2×2×2×5 = 80
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