Hcf of 378,180 and 420 by prime factorisation method is hcf*lcm of three numbers equal to the product of the three numbers
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Solution:-
Prime factors of 378 = 2 × 3 × 3 × 3 × 7
Prime factors of 180 = 2 × 2 × 3 × 3 × 5
Prime factors of 420 = 2 × 2 × 3 × 5 × 7
So, HCF of 378, 180 and 420 is 2 × 3 = 6
And LCM of 378, 180 and 420 is 2 × 2 × 3 × 3 × 3 × 5 × 7 = 3780
So, let us check whether LCM (378, 180 and 420) × HCF (378, 180 and 420) is equal to the product of the three numbers
3780 × 6 = 378 × 180 × 420
22680 ≠ 28576800
Hence LCM*HCF is not equal to the product of the three numbers.
Prime factors of 378 = 2 × 3 × 3 × 3 × 7
Prime factors of 180 = 2 × 2 × 3 × 3 × 5
Prime factors of 420 = 2 × 2 × 3 × 5 × 7
So, HCF of 378, 180 and 420 is 2 × 3 = 6
And LCM of 378, 180 and 420 is 2 × 2 × 3 × 3 × 3 × 5 × 7 = 3780
So, let us check whether LCM (378, 180 and 420) × HCF (378, 180 and 420) is equal to the product of the three numbers
3780 × 6 = 378 × 180 × 420
22680 ≠ 28576800
Hence LCM*HCF is not equal to the product of the three numbers.
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