hcf of 4052&420 in the from of Euclid's division algorithm
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a>b
4052>420
4052=420×9+272
r≠0
420=272×1+148
r≠0
272=148×1+124
r≠0
148=124×1+24
r≠0
124=24×5+4
r≠0
24=4×6+0
∴ the hcf of 4052 and 420 is 4.
4052>420
4052=420×9+272
r≠0
420=272×1+148
r≠0
272=148×1+124
r≠0
148=124×1+24
r≠0
124=24×5+4
r≠0
24=4×6+0
∴ the hcf of 4052 and 420 is 4.
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