Question

HCF of 72, 80 and 120 by Euclid's division Lemma

Answer 1

HEYA MATE HERE GOES UR ANSWER.........

Euclid:  

80/72 leaves a remainder of 8 and 8 divides 72 evenly, so GCD(72,80) = 8.  

8 also divides 120 evenly (8*15 = 120) so GCD(72,80,120) = 8 as well.  

FTA:  

72 = 2^3 * 3^2  

80 = 2^4 * 5^1  

120 = 2^3 * 3^1 * 5^1  

The only common prime factor is 2, and the smallest exponent is 3, so  

GCD(72, 80, 120) = 2^3 = 8

Answer 2

Answer:

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