hcf of fiftytwo and twentysix
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Hi,
According to the problem given,
One number = a = 52
Second number = b = 182
HCF( 52, 182) = H= 26
LCM (52 , 182) = L
We know that ,
H × L = a × b
L = ( a × b )/ H
L = ( 52 × 182 ) / 26
L = 364
Therefore ,
LCM( 52, 182) = L = 364
I hope this helps you.
According to the problem given,
One number = a = 52
Second number = b = 182
HCF( 52, 182) = H= 26
LCM (52 , 182) = L
We know that ,
H × L = a × b
L = ( a × b )/ H
L = ( 52 × 182 ) / 26
L = 364
Therefore ,
LCM( 52, 182) = L = 364
I hope this helps you.
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