Question

Hcf of hcf and lcm of two numbers are 9 and 360 respectively if one number is 45 find the other number

Answer 1

GIVEN:

HCF of two numbers = 9

LCM of those two numbers = 360

One of the numbers = 45

TO FIND:

Another number

SOLUTION:

Let the other number be x

We know that,

Product of two numbers = HCF × LCM

According to the problem,

==> 45 × x = 9 × 360

==> x = (9 × 360) / 45

==> x = 9 × 8

==> x = 72

Therefore, the other number is 72.

Verification:

Product of two numbers = HCF × LCM

==> 45 × 72 = 9 × 360

==> 3240 = 3240

LHS = RHS

Hence, Verified!

Answer 2

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• The other required number = 72

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• H.C.F and L.C.M of two numbers are 9 and 360 respectively.If ine number is 45.

$\sf\underline{\red{\:\:\: Need\:To\: Find:-\:\:\:}}$

• The other required number = ?

$\bf{\underline{\underline \blue{Explanation:-}}}$

$\sf\underline{\red{\:\:\: Formula\:Used\: Here:-\:\:\:}}$

$\bigstar \: \boxed{ \sf \: HCF \times LCM = a \times b}$

$\sf\underline{\green{\:\:\: Now,Putting\:the\: values:-\:\:\:}}$

$\dashrightarrow \sf {12 \times 360 = 60 \times b}$

$\dashrightarrow \sf {\frac{12 \times 360}{60} = b}$

$\dashrightarrow \sf {\dfrac{12 \times \cancel{360}}{ \cancel{60}} = b}$

$\dashrightarrow \sf {b = 72}$

$\sf\underline{\red{\:\:\: ThereFore:-\:\:\:}}$

• The other required number is 72.

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Some more Information:

H.C.F ➪ Highest Common Factor.

L.C.M ➪ Least Common Multiple.

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