hcf of pairs of numbers by division medhod1728, 1632
Answers
Answered by
1
Solution is in the attachment...
Attachments:
Answered by
1
Hi dear
★ Here is your answer ★
Dividing 1728 by 1732
1632 ) 1728 ( 1
''''''''''''''1632
''''''''''''''-----------
''''''''''''''''''96) 1632 ( 17
''''''''''''''''''''''''''1632
'''''''''''''''''''''''''''--------
''''''''''''''''''''''''''''''0
Remainder = 0
hence,
hcf of 1728 and 1632 is 96.
★ Here is your answer ★
Dividing 1728 by 1732
1632 ) 1728 ( 1
''''''''''''''1632
''''''''''''''-----------
''''''''''''''''''96) 1632 ( 17
''''''''''''''''''''''''''1632
'''''''''''''''''''''''''''--------
''''''''''''''''''''''''''''''0
Remainder = 0
hence,
hcf of 1728 and 1632 is 96.
Similar questions
Social Sciences,
8 months ago
Physics,
8 months ago
Math,
8 months ago
Math,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago
Math,
1 year ago