Question

in triangle ABC B-D-C AND BD = 7 BC=20 THEN FIND THE RATIO OF A (ABD ) upon (ADC)

Answer 1

hii
there you answer
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theorems: when two triangle are similar the ratio of areas of those triangle is equal to the ratio of the square of their corresponding sides.

1) A(∆ABD) /A(∆ADC)= BD^2/DC^2
BD^2/ (BC-BD)^2
7^2/(20-7)^2
7^2/13^2

2) A(∆ABD)/ A(∆BC)= BD^2/BC^2
BD^2/BC^2
7^2/20^2

3) A(∆ADC ) /A(∆ ABC) = DC^2/BC^2
(BC-BD)^2/BC^2
( 20-7)^2/20^2
13^2/20^2
it's helpful for you

Answer 2

Answer:

Hey above is your answer