HCF of two numbers in 179 and their LCM is 2685. If one of the numbers in 537, then one of the divisors of the other number is ?
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hcf of two numbers = 179
lcm of two numbers = 2685
one number = 537
Other number = ?
We know that,
hcf × lcm = one number × other number
179 × 2685 = 537 × other number
other number = 895
lcm of two numbers = 2685
one number = 537
Other number = ?
We know that,
hcf × lcm = one number × other number
179 × 2685 = 537 × other number
other number = 895
Answered by
0
Answer:
one of the divisors of the other number is 5
Step-by-step explanation:
Given data
HCF of two numbers is 179
LCF of two numbers is 2685
in the two numbers one of the number is 537
here we need to find one of the divisors of the second number
Note :
The product of LCM and HCF of two natural numbers is equals to the product of the two numbers.
⇒ let x be the another number
⇒ product of lcm and hcf of two numbers = product of two numbers
⇒ 2685 × 179 = 537 (x)
⇒ x = 2685×179 / 537
= 895
One of the divisors of 895 :
Divisors are the numbers which divides the number equally
⇒ 5 is the one of the divisor of 5 which divides 895 equally
⇒ 895/ 5 = 179
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