HCF of two numbers is 15. Then its LCM may be
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If the HCF of the two numbers is 15 then the two numbers are 15*a and 15*b where ‘a’ and ‘b’ are integers.
LCM is a least value of the number divisible by both 15*a and 15*b.
So if you are expecting to know the smallest value for the LCM then a=1 and b= 2 could be a possible solution. This gives the LCM of 15 and 30 as 30.
Here I am assuming the two numbers to be unequal.
Step-by-step explanation:
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therefore, answer is 45
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