HCF of two numbers is 27 and there LCF is 126 if one of the number is 54 then the other number is?
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For two numbers a and b, we know that
(a×b)=HCFof(a,b)×LCMof(a,b)
Here,
a=54,HCF=27,LCM=162
Therefore,
(54×b)=(27×162)
b=
54
27×162
=81
Hence, the other number is 81.
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