Question

HCF of (x^2-1)^2,(x+1) and (x^2-1) is​

Answer 1

Answer:

now we have two polynomial here

1) [x-2][x^2+x-2]

lets factorise it further

=(x-2)(x^2 +x-2)

=(x-2)(x-1)(x+2) factors of polynomial 1

now

2) [x-1] [x^2-3x +2]

lets factorise it further

= (x-1)(x-1)(x-2) factors of polynomial 2

now common factors in both p1 and p2 are

(x-1)and (x-2)

and hcf will be = (x-1)(x-2) = x^2-3x +2 answer

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

(x^2-1)^2=((x+1)(x-1))^2=(x+1)^2(x-1)^2

(x+1)=(x+1)

(x^2-1)=(x+1)(x-1)

HCF=(x+1)