Question

HCF prime factorization method of 176,260 and 612​
Plz answer ASAP

Answer 1

Given that:

• Numbers are 176, 260 and 612.

To Find:

• HCF using prime factorization method.

Finding the HCF:

By prime factorization.

• Factors of 176 = 2⁴ × 11
• Factors of 260 = 2² × 5 × 11
• Factors of 612 = 2² × 3² × 17

HCF (176, 260, 612) = 2² = 4

Hence,

• HCF of 176, 260 and 612 is 4.

Answer 2

Answer:

HCF = 4

Step-by-step explanation:

$\begin{array}{c |l} 2&176 \\ \hline2&88 \\ \hline2&22 \\ \hline11&11 \\ \hline &1 \end{array}$

So, Prime Factorization of 176- 2×2×2×11

$\begin{array}{ c| l}2&260 \\ \hline2&130 \\ \hline5 &65 \\ \hline 13&13 \\ \hline &1 \end{array}$

Prime Factorization of 260 - 2×2×5×13

$\begin{array}{c |l}2&612 \\ \hline 2&306 \\ \hline3&153 \\ \hline3&51 \\ \hline17&17 \\ \hline &1 \end{array}$

Prime Factorization of 612 = 2×2×3×3×7

Prime Factorization of 176- 2×2×2×11

Prime Factorization of 260 - 2×2×5×13

Prime Factorization of 612 = 2×2×3×3×7

In the three one 2 × 2 is common in all, So

HCF = 2×2=4