Question

if the roots of ax²+bx+c=0 are in the ratio p:q show that √p/q+√p/q+√c/a=0​

Answer 1

Answer:

ax² + cx  + c = 0

Let  say roots are

α & β

Then α/β = p/q

α + β = - c/a

αβ = c/a

√p/q+√q/p+√c/a=0​

LHS = √p/q+√q/p+√c/a

= √α/β+√β/α+√c/a

= (α + β)/√αβ  + √c/a

= (- c/a)/√c/a + √c/a

= - √c/a + √c/a

= 0

= RHS

Step-by-step explanation:

Answer 2

Answer:

HOPE it helps you.

Sorry if it is wrong