HE¥A!!
From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameteris cut off. Find the area of remining paper (use π = 22/7)
❌PLEASE Don't SPAM ❌
Answers
Answered by
2
Answer:
ÀB = 40 cm
AD = 28cm
opposite sides are equal
AB = CD & BC = AD
diameter is given d = 28 so radius is D = r / 2 => 14
remain portion of paper area
AB + BC + CD + DA - 22/ 7 × BC
40 + 40 + 28 + 28 - 22/ 7 × 14
80 + 56 - 22 × 2
136 - 44
92 cm
Answered by
0
Answer:
Length of paper, AB = l = 40cm
Width of paper, AD = b = 28cm
Area of paper = l × b = 40 × 28 = 1120 cm²
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2 πr²
= 1/2 × 22/7 × 14 × 14
= 308 cm²
∴ Area of remaining paper = 1120 – 308
= 812 cm²
Similar questions