Question

ᴛhe breaks applied to a car produce an acceleration of 6m/s 2 in the opposite direction to the motion. If the car takes 2s to stop after the application of breaks , calculate the distance it travels during this time.

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ᴀᴀᴊ ᴀɴꜱᴡᴇʀ ᴍɪʟᴇɢᴀ ʙʜɪ ᴋɪ ꜱɪʀꜰ ꜱᴀᴀʙ ᴍᴇʀᴀ Qᴜᴇꜱᴛɪᴏɴ ᴘᴀʀ ᴀɴꜱᴡᴇʀ ʜɪ ᴋᴀʀᴏɢᴀ .
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Answer 1

Answer:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m

Explanation:

I hope it will help you

Answer 2

Answer your Krishna drawing is very nice

Explanation:

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