he cost of fencing a garden which is in the shape of a Trapezium is ₹1 1250 at the rate of Rs 50 per metre. Find its height if its parallel sides are 20 and 25 m long
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The cost of fencing 1m² = ₹50
// // // // xm² = ₹11250
Since cost of fencing xm² × ₹50 = ₹11250
⇒ xm² =₹11250/₹50
⇒ x =225m²
ₒᵒₒ Ar. of the trap. = 225m²
Also,
Ar. of a trap. = 1/2×h×(sum of // sides)
⇒ 225m² = 1/2×h(20m+25m)
⇒ 225m² = 1/2×h×45m
⇒(225m²/45m)×2 = h
⇒ h = 10m
// // // // xm² = ₹11250
Since cost of fencing xm² × ₹50 = ₹11250
⇒ xm² =₹11250/₹50
⇒ x =225m²
ₒᵒₒ Ar. of the trap. = 225m²
Also,
Ar. of a trap. = 1/2×h×(sum of // sides)
⇒ 225m² = 1/2×h(20m+25m)
⇒ 225m² = 1/2×h×45m
⇒(225m²/45m)×2 = h
⇒ h = 10m
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