Question

he diameter in of a circle is 41 cm and q is a point on its circumference such that MQ is 9 cm find in NQ?
option 1 . 55
2. 40
3. 42
4. 60​

Answer 1

Solution-:

• We know that perpendicular drawn from the centre of the circle to the chord bisect the chord

• PR=RQ=40 unit
• In ∆ OPR,
• OR² + PR²=OP²
• =>OR² + 40²=41²
• =>OR² + 40²=41²=>OR² + = 1681 - 1600
• =>OR² + 40²=41²=>OR² + =1681 - 1600=>OR² = 80 (unit)

• So 80 – 40 = 40 (units)

ANSWER -: 40

HENCEFORTH OPTION 2nd IS CORRECT

Answer 2

Answer:

yyy

Step-by-step explanation: