he distance of the point ( 5 , - 2 ) from x-axis is : (1 Point) 5 Units - 2 Units 2 Units - 5 Units
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(2,0) and (8,0)
Let the point on x.axis be (k,0)
Now using distance formula we have
Using distance formula we have
(k−5)
2
+(0+4)
2
=5
(k−5)
2
+16
=5
squaring both sides,we have
(k−5)
2
+16=25
(k−5)
2
=9
∴k=8,2
Point is (2,0),(8,0)
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