Math, asked by naveenkolli8741, 9 months ago

He following two questions refer to the circuit below.


consider a non-ideal op amp where the output can saturate.


the open loop gain a = 2 x 10410^{4}104, where vov_{o}vo​=−avsv_{s}vs​.


the positive supply voltage for the op-amp is +vs=15+v_s = 15+vs​=15v. the negative supply voltage for the op-amp is −vs=−10-v_s = -10−vs​=−10v.


what is the most positive value vsv_{s}vs​ can take before the amplifier saturates? express your answer in mv and omit units from your answer.

Answers

Answered by rounik30
2

Step-by-step explanation:

1

The following two questions refer to the circuit below.

Consider a non-ideal op amp where the output can saturate.

The open loop gain A = 2 x 10^4, where vo?= ?Avs.

The positive supply voltage for the op-amp is +VS = 15v. The negative supply voltage for the op-amp is ?VS= ?10v.

What is the most positive value vs can take before the amplifier saturates? Express your answer in mV and omit units from your answer.

2

For the circuit above in question 1, what is the most negative value vs? can take before the amplifier saturates? Express your answer in mV and omit units from your answer.

15 V 0 Vo

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