Question

he hcf and lcm of two numbers are 11 and 385 respectively. if one number lies between 75 and 125, then that number is :

Answer 1

since, we have given H.C.F = 11 of required numbers then definitely required number will be the multiple of 11.

let the numbers are 11a ,11b

product of two numbers = H.C.F × L.C.M

11a × 11b = 11 × 385

121 ab = 4235

ab = 35

a × b = 5 × 7

so now the required numbers are

11a = 11 × 5 = 55

11 b = 11 × 7 = 77

therefore, the number lies between 75 and 125 = 77.

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Your Answer : 77
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Answer 2

since, we have given H.C.F = 11 of required numbers then definitely required number will be the multiple of 11.

let the numbers are 11a ,11b

product of two numbers = H.C.F × L.C.M

$11a × 11b = 11 × 385$

$121 ab = 4235$

$ab = 35$

$a × b = 5 × 7$

so now the required numbers are

$11a = 11 × 5 = 55$

$11 b = 11 × 7 = 77$

therefore, the number lies between 75 and 125 = 77.

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Your Answer : 77

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