he hypotenuse of right triangle is 20m. if the difference between the length of the other sides is 4 m. find the other sides
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let the other sides be x and y.
then
x²+y²=20²,
x²+y²=400, .......eq(1),
also
x-y=4,........eq(2),
using these two equastion we get
x=16 m,
y=12 m
then
x²+y²=20²,
x²+y²=400, .......eq(1),
also
x-y=4,........eq(2),
using these two equastion we get
x=16 m,
y=12 m
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