Question

he larger of two complementary angles exceeds the smaller by 18 find them

Answer 1

The solution is in the attachment..

Answer 2

Let angles be x and y

and x angle is larger

Situation First,

$x + y = 90................. |i|$

Situation second,

$x = y + 18 \\ x - y = 18......... |ii|$

Add eq first and second,

$x + y = 90 \\ x - y = 18 \\ 2x = 108 \\ x = 54$

so x+y=90

54+y=90

y=90-54

y= 36