Question

He length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally along a diagonal order to catch a rat. How much total distance is cover

Answer 1

Perimeter=2(l+b)

l=8m,b=6m

2(8m+6m)

=2(14m)

=28m

therefore the total distance is cover is 28meters

Answer 2

Answer:

38 meters

Step-by-step explanation:

The total distance would be the perimeter of the room + the hypotenuse... So here we are talking of the perimeter of a rectangle in the first part  

First Part

Perimeter is just the sum of all sides, there are 2 sides with the length of 6 m and 2 sides with the length of 8 m so...

6m + 6m + 8m + 8m = 28m

Second Part

Now since 1 side of the rectangle is 6m and one side is 8m we can apply the pythagorus theorem which is an follows.

a^2 + b^2 = c^2

6^2 + 8^2 = ?

36 + 64 = 100

100 = c^2

square root of c^2 equals 10

Putting it together

So as mentioned in the beginning this problem involves the perimeter and hypotenuse of the room therefore the perimeter which is 28m plus the hypotenuse which is 10m added together...

28m + 10m = 38m

which makes your answer 38m

Hope that helped.