He length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally along a diagonal order to catch a rat. How much total distance is cover
Answers
Perimeter=2(l+b)
l=8m,b=6m
2(8m+6m)
=2(14m)
=28m
therefore the total distance is cover is 28meters
Answer:
38 meters
Step-by-step explanation:
The total distance would be the perimeter of the room + the hypotenuse... So here we are talking of the perimeter of a rectangle in the first part
First Part
Perimeter is just the sum of all sides, there are 2 sides with the length of 6 m and 2 sides with the length of 8 m so...
6m + 6m + 8m + 8m = 28m
Second Part
Now since 1 side of the rectangle is 6m and one side is 8m we can apply the pythagorus theorem which is an follows.
a^2 + b^2 = c^2
6^2 + 8^2 = ?
36 + 64 = 100
100 = c^2
square root of c^2 equals 10
Putting it together
So as mentioned in the beginning this problem involves the perimeter and hypotenuse of the room therefore the perimeter which is 28m plus the hypotenuse which is 10m added together...
28m + 10m = 38m
which makes your answer 38m
Hope that helped.