He piston of a hydraulic automobile lift is 0.30 m in diameter. what gauge pressure, in pascals, is required to lift a car with a mass of 1500 kg?
Answers
pr=F/area. =1500×9.8/0.070686 Pa
207961 Pa
The gauge pressure required to lift a car with a mass of 1500 kg is approximately 44,420 Pa.
Given:
Diameter of the piston = 0.30,
Mass of car = 1500kg.
To find:
The gauge pressure to lift the car.
Solution:
The pressure required to lift a car with a mass of 1500 kg can be calculated using the equation:
pressure = force / area
Where the force is equal to the weight of the car, and the area is equal to the cross-sectional area of the piston.
The weight of the car can be calculated as:
force = mass * acceleration due to gravity
force = 1500 kg * 9.8 m/s^2
The cross-sectional area of the piston can be calculated as:
area = (π/4) * diameter^2
area = (π/4) * 0.30 m^2
Putting it all together:
pressure = force / area
pressure = (1500 kg * 9.8 m/s^2) / ((π/4) * 0.30 m^2)
pressure = approximately 44,420 Pa.
So, the gauge pressure required to lift a car with a mass of 1500 kg is approximately 44,420 Pa.
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