Question

How can we produce the terms of a sequence if the first 10 terms are 5, 11, 17, 23, 29, 35, 41, 47, 53, 59?

Answer 1

Answer:

d=11-5=6

an=a+(n-1)d

an=5+(n-1)6

an=5+6n

Answer 2

Concept Introduction:-

It would possibly resemble a phrase or various illustration of the quantity's mathematics price. It ought to resemble a phrase or various that represents the numerical price of the quantity.

Given Information:-

We have been given that the first $10$ terms are $5, 11, 17, 23, 29, 35, 41, 47, 53, 59$.

To Find:-

We have to find that how can we produce the terms of a sequence if the first $10$ terms are $5, 11, 17, 23, 29, 35, 41, 47, 53, 59$.

Solution:-

According to the problem

The Formula which is used in the question $a_n=a+(n+1)d$

The common difference in the given question is $d=11-5=6$

$a_n=a+(n-1)d\\a_n=5+(n-1)6\\a_n=5+6n-6\\a_n=6n-1$

Final Answer:-

The correct answer is the terms of a sequence if the first $10$ terms are $a_n=6n-1$.

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