Question

He square of a two digit number is divided by half the number. after 36 is added to the quotient, this sum is then divided by 2. the digits of the resulting number are the same as those in the original number, but they are in reverse order. the difference between its digits

Answer 1

[(x^2 / 0.5x)+36]/2 = x+18            .....................................(1)

If the two digits of the number "x" are A(tens) and B(ones), then the number would be 10A + B.

As per equation (1) above 10A + B + 18  = 10B + A

ie., 9B - 9A = 18

B - A =2.

Hence the difference between the two digits should be 2.

A should be even as it should be divisible by 2. Hence the possible nos. would be 24, 46 or 68