he start the run exactly at 2:30pm and the tract is 500 m in circumference. he run twice on a circular track at a uniform speed. speed 12km/hr. when does he finish the 2nd lap..
Answers
Distance= 500 m
Time = D/S = 500/3.33 = 150.15 seconds or 150 s or 2.5 minutes
By the time second lap will end 5 minutes would have been passed.
Therefore Time= 2:35 pm
Hope it helps ^_^
Step-by-step explanation:
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┴┬┴┬┴┬┴ ＼＿＿＿＼ ﹨＿＿＿＿＼Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
⬤•━━━━━━━━━━Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
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┴█████ ██████◤ ﹨
┬│ │█████ ◤ ▏
┴│ │ ▏
┬∕ ∕ ／▔▔▔＼ ∕
*∕＿＿_／﹨ ∕ ﹨ ／
┬┴┬┴┬┴＼ ＼_ ﹨ ＼_
┴┬┴┬┴┬┴ ＼＿＿＿＼ ﹨＿＿＿＿＼Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
Hence, the answer is 15.
⬤•━━━━━━━━━━Given: d=3
We know:
an=a+(n−1)d
∴a20−a15=[a+19d]−[a+14d]
=5d
=5×3
=15
- Hence, the answer is 15.
┴┬┴┬／￣＼＿／￣＼
┬┴┬┴▏ ▏▔▔▔▔＼
┴┬┴／＼ ／ ﹨
┬┴∕ ／ ）
┴┬▏ ● ▏
┬┴▏ ▔█◤
┴◢██◣ ＼＿＿／
┬█████◣ ／
┴█████████████ ◣
◢██████████████▆▄
█◤◢██ ◣◥█████████ ◤＼
◥◢ ████ ████████◤ ＼
┴█████ ██████◤ ﹨
┬│ │█████ ◤ ▏
┴│ │ ▏
┬∕ ∕ ／▔▔▔＼ ∕
*∕＿＿_／﹨ ∕ ﹨ ／
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