Question

he sum of the digits of a two-digit number is 9. Also, nine times this number is
rive the number obtained by reventing the order of the digits. Find the number
plz do it in elimination process.
i need it ..............​

Answer 1

Answer:

I don't know but I will try later because I don't have this much time because I also want to sleep

Answer 2

Answer:

18

Step-by-step explanation:

Let the digit in one's place be x and the digit in ten's place be y.

Original number = 10y +  x.

Number formed by reversing the digits = 10x + y.

(i)

Sum of digits of a two-digit number is 9.

x + y = 9

(ii)

Nine times the number is twice the number obtained

⇒ 9(10y + x) = 2(10x + y)

⇒ 90y + 9x = 20x + 2y

⇒ 88y - 11x = 0

⇒ 8y - x = 0

⇒ x - 8y = 0

On solving (i) & (ii) by using elimination process, we get

x + y = 9

x - 8y = 0

---------------------

9y = 9

y = 1

Substitute y = 1 in (i), we get

⇒ x + y = 9

⇒ x + 1 = 9

⇒ x = 8

∴The original number = 10y + x = 18.

Hope it helps!