He sum of two numbers is 184. If one-third of the one exceeds one-seventh of the other by 8, find the smaller number.
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Answered by
8
GIVEN
Let one of the number be x
The other number will be 184 - x
Difference is 8
According to the Question ,
1/3 of x exceed 1/7 of 184-x by 8
1/3 x - 1/7 (184 - x) = 8
=> x/3 - (184 - x) / 7= 8
=> [7x - 3(184 - x)]/21 = 8
=> [7x- 552 + 3x]/21 = 8
=> 10x - 552 = 21 × 8
=> 10x = 168 + 552
=> 10x = 720
=> x = 72
The other number will be 184 - 72=112
Therefore the smallest number is 72(Ans)
Answered by
6
The correct answer is 72.
Refer to given attachment
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