Question

he volume charge density of a solid sphere of radius 0.75 metre is 0.25 apply gauss law to calculate the electric flux through the sphere and electric field at a distance of 1.5 metre and a distance of 0.5 m from the centre of the sphere respectively if this sphere were made of conducting material what would the value of the electric field be at these distances

Answer 1

Answer:

Explanation:

 

Question #86382, Physics / ElectromagnetismElectric field inside and outside of uniformly charged solid sphere:Radius of the charged solid sphere (R= 0.75 m)Volume charged density of solid sphere (ρ = 0.25 푛퐶/푚3)Electric charge on sphere (Q)푄=ρVWhere V is volume of solid sphere i.e. (43휋푅3)Q = Total charge enclosed by the sphere.(a)Electric flux through the sphere Flux = ∮퐸.푑푠= E*A          Where A = electric field passing through the surface= E*4*휋*푅2E = Electric field on the surface.(Note: We can find electric field by substituting radius of solid sphere in the formula of electric field inside the solid sphere as given below)(b)Electric field insidethe solid sphere i.e. (radius of Gaussian sphere= 0.5m)∮퐸.푑푠=푄′휖∮퐸∗푑푠∗cos90°=푄′휖Since E and ds are perpendicular to each other.퐸∗4휋푟2=휌∗43휋푟3/휀퐸=휌푟3휀On substituting valuesE = 0.25∗0.5∗10−93∗8.85∗10−12푁/퐶E =0.0047 * 103N/C•Electric field outsidethe solid sphere i.e. (radius of Gaussian sphere = 1.5∮퐸.푑푠=푄휖∮퐸∗푑푠∗cos90°=푄휖Since E and ds are perpendicular to each other.퐸∗4휋푟2=휌∗43휋푅3/휀퐸=휌푅33휀푟2E = 0.0017* 103N/C

(c)If this sphere were made of conducting material thenElectric field inside the conductor will be zero and