Question

Hea
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In the figure, mZC = m_D = 90° and
BC = AD. Prove that AC = BD, and
ZBAC ZABD.​

Answer 1

In ∆ABC and ∆ABD

angle BDA=angle ACB(90⁰each)

BC=AD (given)

AB=AB (common)

by SAS criteria

∆ABC ≈(congruent ) ∆ABD

so AC=BD (crossponding part of congruent∆ , short form CPCT)

and angle BAC= angle ABD (CPCT)

hence proved

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