Question

three resistance each of 8ohms are connected to a triangle then resistance between any two terminals​

Answer 1

R=R1+R2+R3

R= 8+8+8

R= 24ohm

Hope this will help u.

Answer 2

Answer:

Req. = 16/3 ohms

Explanation:

Let three resistances be R1, R2, and R3.

R1 = R2 = R3 = 8ohms

R1, R2 & R3 are connected in as the sides of a triangle.

Consider two points A and B such that, R1 & R2 are connected in series, while R3 is connected in parallel.

So, (R') = R1 + R2 = 8 + 8 = 16 ohms

R3 = 8 ohms

Now, (R') is parallel to R3.

So, 1/Req. = 1/R' + 1/R3

1/Req. = 1/16 + 1/8 = (1 + 2)/16

Req. = 16/3 ohms

Thanks!