Heat energy absorbed by a system going through a cyclic process as shown in figure is
a) 10⁷ pi Joule
b) 10⁴ pi Joule
c) 10² pi Joule
d) 10^-3 pi Joule
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Answer:
C
Explanation:
Since process is cyclic, change in internal energy ΔU=0
Applying first law of thermodynamics,
ΔQ=ΔU+ΔW
ΔQ=ΔW = Area under the ellipse= πab
Here, length of semi major axis=a=10=b=length of semi minor axis
Hence, heat absorbed= 10
2
π J
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