Question

heat engine rejects 600 cal to sink at 27 celcius. amount of work done by engine will be?

Answer 1

According to question

Energy = 600 Cal
             =  600 * 4184 Joules
             = 2510400 J
Also
Temprature 
    T = 27 Celcius
      =  300 K

Thus Work Done = Energy /  Temprature
                            = 2510400 / 300
                            = 833466.66 J

Answer 2

Hey dear,

● Answer -
W = 1680 J

● Explanation -
T1 = 27 °C = 300 K
T2 = 227 °C = 500 K
Q1 = 600 cal = 2520 J

# Solution -
In heat engine,
Q1 / Q2 = T1 / T2
Q2 = Q1 × T2 / T1
Q2 = 2520 × 500 / 300
Q2 = 4200 J

Work done by heat engine is calculated by formula -
W = Q2 - Q1
W = 4200 - 2520
W = 1680 J

Therefore, work done by engine is 1680 J.

Hope this helped you...