Heat=I²RT.Here resistance is directly proportional to heat but H=V²T/R and here resistance is inversely proportional to heat.So,will the resistance increase or decreases in increasing the temperature(heat)?plss explain clearly!!!!!!!!!!!!!!!!!!!
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Answered by
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in the first equation I.e,
H=I^2RT
here with increased in temperature heat produced will also be increased. hence resistance will be large as H is directly proportional to R.
in the second equation
H=V^2T/R
R=V^2T/H
when H increase R decrease and vice versa.
so,the two conditions for the resistances are different, due to the involvement of potential different in the second equation.
H=I^2RT
here with increased in temperature heat produced will also be increased. hence resistance will be large as H is directly proportional to R.
in the second equation
H=V^2T/R
R=V^2T/H
when H increase R decrease and vice versa.
so,the two conditions for the resistances are different, due to the involvement of potential different in the second equation.
Answered by
0
Answer:
heat is directly proportional to amount of heat
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