Question

Heat of 25 kcal is supplied to a system
and 4200 J of external work is done on
the system so that its volume decreases
at constant pressure. What is the
change in its internal energy. (J = 4200
J/kcal)​

Answer 1

Answer:

Triangle Q=30 × 4200

12 600 J

Triangle W = -4200J

so. Traingle U= Traingle U - Traingle W

126000 + 4200

1.302 ×10⁵.

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Answer 2

Answer:

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Explanation:

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