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Heat of combustion of benzene is 718 K.cals. When 39 gms of benzene undergoes combus
tion, the heat liberated is
1) 718 K.cals . 2) 359 K.cals 3) 135 K.cals
4) 1436 K.cals
plz help me!!! guys
Answers
Answered by
0
Answer:
Here is your Anwer
Explanation:
The Correct option is 1st:718k.cals
Answered by
0
Answer:
359
Explanation:
C6H6=78g
78g of C6H6 on combustion gives 718kcal
39g ". ". ". ". ". (718*39)/78
=359 kcal
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