Question

Heat of neutralization of a strong acid and strong base is -57.0 kJmor', the enthalpy
change of 0.5mole HNO, with 0.5 mole KOH will be
ps: i need solution please ​

Answer 1

Answer:

- 28.5 KJ

Explanation:

for 1mol heat of neutralization = -57.5 KJ

for 0.5 mol heat of neutralization = -57.5KJ×0.5=-28.5KJ