Question

Heat required to melt only 1000 grams of ice is

Answer 1

q1 = heat required to melt the ice to water at 0.00 °C. q2 = heat ... q2=mc ΔT=100.g×4.184J1°C∙g×100.00°C = 41 800 J.

Answer 2

The heat required to melt only 1000 grams of ice is 333.55 kJ.

• The latent heat of fusion, which is also called the enthalpy of fusion, can be defined as the amount of heat or energy required to be supplied or provided to a unit mass of a solid so as to convert it into liquid.
• Now, we know that the latent heat of fusion of water or ice is about 333.55 kJ/kg.
• It implies the amount of heat that must be supplied to melt 1 kg or, 1000 g of ice will be about 333.55 kJ.
• Thus, the heat required to melt only 1000 grams of ice is 333.55 kJ.

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