Question

Heats of formation of A, B, C and D are -50, -80, +50 and +80 kJ mol-1. The order of stability is
(A) AB > C >D
(B) B >A>C>D
(C) B >A>D>C
(D) A>B>D>C​

Answer 1

Answer:

b is correct ans

Explanation:

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Answer 2

The order of stabilty is B>A>C>D. (Option C)

Given:

Heats of formation of A, B, C and D are -50, -80, +50 and +80 kJ mol-1.

To Find:

The order stability of A, B, C and D.

Solution:

The heat of formation is the amount of heat absorbed or evolved when one mole of a compound is formed from its constituent elements, each substance being in its normal physical state (gas, liquid, or solid).

The more negative the heat of formation, the greater is the stability.

Here B has the most negative heat of formation and D has a positive value.

So, B is the most stable and D is the least.

A has more negative heat of formation than C but less than B.

So, the order of stability is B>A>C>D.

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